A lot of 40 spacing washers contains 30 washers that are thicker than the target dimension. Suppose that three washers are selected at random, without replacement, from the lot. Round your answers to four decimal places (e. g. 98.7654). (a) What is the probability that all three washers are thicker than the target? (b) What is the probability that the third washer selected is thicker than the target if the first two selected are thinner than the target? (c) What is the probability that the third washer selected is thicker than the target?

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

it shoild be o

step-by-step explanation:

it would take 5 hours i think idk i'm not that good at math.can you me with my questions i need asap.

t hope this

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