Fiona wrote the predicted and residual values for a data
set using the line of best fit y-3.71X-8.85.
Which statements are true about the table? Select three
options
The data point for x = 1 is above the line of best fit
Given
-5.1
-1.3
Residual
0.04
Predicted
-5.14
-1.43
2.28
The residual value for x = 3 should be a positive number
because the data point is above the line of best fit.
-0.13
CN
1.9
-0.38
0.21
6.2
5.99
Fiona made a subtraction error when she computed the
residual value for x = 4.
The residual value for x = 2 should be a positive number
because the given point is above the line of best fit.
The residual value for x = 3 is negative because the
given point is below the line of best fit,

  5.   y=6; de=7; fg=8

  6.   x=4.2; jl=14.2; mn=13

step-by-step explanation:

when chords cross inside a circle, the product of the segment lengths is a constant.

5. dh×eh = fh×gh

  y = gh = dh×eh/fh = 3×4/2 . . . divide by the coefficient of gh

  y = 6

of course, the total chord length is the sum of the lengths of its segments.

  de = dh +eh = 3+4 = 7

  fg = fh +gh = 2+6 = 8

6. this problem works the same way as the previous one.

  x = lk = mk×nk/jk = 6×7/10 = 4.2

  jl = jk +lk = 10 +4.2 = 14.2

  mn = mk +nk = 6 +7 = 13

comment on chords and secants

you can think of the points h (problem 5) and k (problem 6) as points where the chords meet. a chord is part of a secant line, a line that intersects the circle in two points. one can also consider these points (h or k) to be the points where the respective secant lines meet.

then, the product that is a constant is the product of the distance from the meeting point (h or k) to one circle intersection with the distance from that meeting point to the other circle intersection. for problem 5, the constant is the product hd×he = hf×hg.

it turns out that this rule regarding the products of lengths to points of intersection is also true when the secants intersect outside the circle.

that is, you only need to remember one rule to work both kinds of problems.

you can't solve x because it is 2 linear equation and you only have one equation

yes the data was not prsented

step-by-step explanation: