On a coordinate plane, a line is drawn from point A to point B. Point A is at (9, negative 8) and point B is at (negative 6, 7).
What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is Two-thirds the length of the line segment from A to B?

x = (StartFraction m Over m + n EndFraction) (x 2 minus x 1) + x 1

y = (StartFraction m Over m + n EndFraction) (y 2 minus y 1) + y 1

(2, –1)
(4, –3)
(–1, 2)
(3, –2)

Option D: is the coordinates of the point P

Explanation:

The coordinate of point A is

The coordinate of point B is

The length of the point P is of the line segment from A to B.

The coordinates of the point P can be determined using the formula,

 and  

where .

Substituting the values, we have,

Similarly, substituting the values for y, we get,

Thus, the coordinates of the point P is

Hence, Option D is the correct answer.

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

my answer is$ 12

step-by-step explanation:

because 15 -2=12