Trapezoid jklm is shown on the coordinate plane below:
trapezoid jklm on the coordinate plane with ordered pairs at j negative 6, 5, at k negative 3, 5, at l negative 1, 2, at m negative 8, 2.
if trapezoid jklm is translated according to the rule (x, y) → (x + 2, y − 6), what are the coordinates of point l'?

The Coordinate of point L' is (1,-4)

Step-by-step explanation:

Trapezoid JKLM on the coordinate plane with ordered pairs

J(-6,5)

K(-3,5)

L(-1,2)

M(-8,2)

If trapezoid JKLM is translated according to the rule (x, y) → (x + 2, y − 6)

We need to find the coordinate of L'

L(-1,2)

(x, y) → (x + 2, y − 6)

Rule of translation: x-coordinate shift 2 unit right and y-coordinate shift 6 unit down.

    L → L'

(-1,2) → ( -1+2, 2-6)

(-1,2) → (1,-4)

Hence, The Coordinate of point L' is (1,-4)

i can't solve unless i know what the line is

step-by-step explanation:

welcome to/p>

step-by-step explanation:

what was your answer?