The equation of the line wx is 2x plus y equals -5 what is the equation of a line perpendicular to line wx in slope intercept form that contains point negative one -2

Step-by-step explanation:

The equation of the line WX is, 2x + y = - 5

⇒ y = - 2x - 5 .......... (1)

This equation is in slope-intercept form and the slope is - 2 and the y-intercept is - 5.

Now, if a line perpendicular to equation (1) having slope m then, m × (- 2) = - 1

⇒

{Since the product of slopes of two mutually perpendicular straight line is - 1}

Therefore, the equation of the perpendicular line is

, where c is a constant and we have to find it.

This above line passes through the point (-1,-2) and hence

⇒

Therefore, the equation of the line will be (Answer)

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

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step-by-step explanation: