Help please asap please

hyp = √617 m

Step-by-step explanation:

In other words, we have a right triangle with leg lengths 16 m and 19 m, and need to find the length of the hypotenuse.

To do this, use the Pythagorean Theorem:

(leg 1)^2 + (leg 2)^2 = (hypotenuse)^2

Then (16 m)^2 + (19 m)^2 = (hyp)^2, or:

256 m^2 + 361 m^2 = (hyp)^2, or:

      617 m^2             = (hyp)^2

Then the length of the hypotenuse is hyp = √617 m

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116