Create the equation of a quadratic function, in standard form, that has one zero of -3 and a turning point at (-1,-16)

Step-by-step explanation:

we know that

The quadratic equation in vertex form is equal to

where

a is the leading coefficient

(h,k) is the vertex of the quadratic equation

Remember that

In a quadratic equation the turning point is the same that the vertex

so

(h,k)=(-1,-16)

substitute

we have one zero at (-3,0)

substitute and solve for a

substitute

Convert to standard form

the answer to the question is a  

it has the same slope and the same y-intercept.

it is only things thain can be deafeated

step-by-step explanation: