How to find the perimeter of a(−5,−1),b(−1,−1),c(−1,−4),d(−5,−4)

The perimeter of ABCD will be 14 units.

Step-by-step explanation:

Points A(-5,-1) and B(-1,-1) lies on the same line which is parallel to the x-axis.

So, length of line segment AB will be |- 5 - (- 1)| = 4 units.

Points B(-1,-1) and C(-1,-4) lies on the line which is parallel to the y-axis.

So, length of line segment BC will be |- 4 - (- 1)| = 3 units.

Points C(-1,-4) and D(-5,-4) lies on the same line which is parallel to the x-axis.

So, length of line segment CD will be |- 5 - (- 1)| = 4 units.

Points D(-5,-4) and A(-5,-1) lies on the line which is parallel to the y-axis.

So, length of line segment DA will be |- 4 - (- 1)| = 3 units.

Therefore, the perimeter of ABCD will be (4 + 3 + 4 + 3) = 14 units. (Answer)

d

step-by-step explanation:

i used the pitagoras theoreme

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form