Sean reads on monday tuesday and wednesday. he reads 3 times as many minutes on tuesday as he does on monday. he reads 4 times as many minutes on wednesday as he does on monday. sean reads 45 minutes on tuesday. how many minutes does sean read on wednesday?

Sean reads 60 minutes on wednesday

Solution:

Given that,

Let "x" be the number of minutes read on monday

Let "y" be the number of minutes read on tuesday

Let "z" be the number of minutes read on wednesday

He reads 3 times as many minutes on Tuesday as he does on Monday

Number of minutes read on tuesday = 3 times the number of minutes read on monday

y = 3x eqn 1

He reads 4 times as many minutes on Wednesday as he does on Monday

Number of minutes read on wednesday = 4 times the number of minutes read on monday

z = 4x eqn 2

Sean reads 45 minutes on Tuesday

y = 45

Substitute y = 45 in eqn 1

45 = 3x

x = 15

Substitute x = 15 in eqn 2

z = 4(15)

z = 60

Thus he reads 60 minutes on wednesday

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true