The sum of four consecutive integers if the first integer is x.

The sum of four consecutive integers if the first integer is x

x + x+y+x+2 y + x+3 y = 4 x + 6 y

Step-by-step explanation:

Explanation:-

Let x, y are two integers are in Arithmetic progression

In Arithmetic progression the four consecutive integers are starting integer 'x'

x , x+y , x+2 y , x+3 y

The sum of four consecutive integers if the first integer is x

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation:

geometry: triangles

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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