Reflect the point (2, -4) over the y-axis. question 1 options: (2, 4) (-2, -4) (-4, 2) (-2, 4) question 2 will mark the brainliest

The image when (2, -4) is reflected over the y-axis is (-2, -4)

The rule for reflection over the y-axis is:

(x, y) >>>> (-x,  y)

This means that the point on the x-axis will be negated but the point on the y-axis will remain the same

If a point (2,  -4) is reflected over the y-axis:

This means that, x = 2, y = -4

-x  =  -2

Therefore, the image when (2, -4) is reflected over the y-axis is (-2, -4)

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The coordinates of the image point will be (-2,-4).

Step-by-step explanation:

The reflection of the point (2,-4) over the y-axis is to be determined.

Now, as the reflecting mirror is the y-axis, then the y-coordinate of the reflecting point will not change.

So, the image point will have coordinates (h,-4).

Now, after the reflection over the y-axis, the x-coordinate of the image point will change the sign only compared to the original point.

Therefore, the coordinates of the image point will be (-2,-4). (Answer)

question

what is the value of the third quartile of the data set represented by this box plot? a. 19 b. 21 c. 26 d. 29

answer

c

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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