The graph attaches shows the function f(x) and the table represents the function g(x)

which statement is true?

a the x-intercept of f(x) is equal to the x-intercept of g(x)

b the y-intercept of f(x) is equal to the y-intercept of g(x)

c the y-intercept of f(x) is greater than the y-intercept of g(x)

d the x-intercept of f(x) is greater than the x-intercept of g(x)

Statement D is true

Step-by-step explanation:

We should know the following:

x-intercept is the value of x when y = 0

y-intercept is the value of y when x = 0

As shown on the graph, we can deduce the following:

For f(x) : at y = 0 ⇒ x = 1  And at x = 0 ⇒ y = -1

So, for f(x) ⇒ x-intercept = 1  & y-intercept = -1  

For g(x) : at g(x) = 0 ⇒ x = -1  And at x = 0 ⇒ g(x) = 1

So, for g(x) ⇒ x-intercept = -1  & y-intercept = 1  

Comparing the results with the given options:

A) the x-intercept of f(x) is equal to the x-intercept of g(x)          (Wrong)

B) the y-intercept of f(x) is equal to the y-intercept of g(x)          (Wrong)

C) the y-intercept of f(x) Is greater than the y-intercept of g(x)   (Wrong)

D) the x-intercept of f(x) is greater than the x-intercept of g(x)   (true)

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]