Use the distributive property to write five expressions that are equivalent to 20x + 100

20x + 100 = the following:

2(10x + 50)

4(5x + 25)

5(4x + 20)

10(2x + 10)

20(x + 5)

Step-by-step explanation:

Use the reverse of the distributive property, which is factoring.

The terms, 20x and 100, have common factors (numbers they can all divide by and get a whole number). When finding common factors, "forget" about the variable first.

They are all divisible by 2, 4, 5, 10 and 20. Write five new expression with the five common factors by "taking out" the common factor from each term in the expression.

Divide each term by 2:

2 (10x + 50)

Divide each term by 4:

4 (5x + 25)

Divide each term by 5:

5 (4x + 20)

Divide each term by 10:

10 (2x + 10)

Divide each term by 20:

20 (x + 5)

think about it deeply and passionately about this property

i am sorry

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.