What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 2.5×10-4 mm (0.9843×10-5 in.) and a crack length of 4×10-2 mm (1.575×10-3 in.) when a tensile stress of 100 MPa (14500 psi) is applied?

1788.9 MPa

Explanation:

The magnitude of the maximum stress (σ) can be calculated usign the following equation:

Where:

ρ: is the radius of curvature = 2.5x10⁻⁴ mm (0.9843x10⁻⁵ in)

σ₀: is the tensile stress = 100x10⁶ Pa (14500 psi)

2a: is the crack length = 4x10⁻² mm (1.575x10⁻³ in)

Hence, the  maximum stress (σ) is:

Therefore, the magnitude of the maximum stress is 1788.9 MPa.

I hope it helps you!

no he didnt use it

explanation:

he said no

answer:

constructing a building's framework requires a solid foundation

explanation: