Mathematics, 29.01.2020 05:59 Isabella1319

The only solution of the equation x2 + bx + 16 = 0 is x = 4. what is the value of b?

b = –16
b = –8
b = 8
b = 16

Answers: 1

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Answer from: ghst

To factor out x2 + bx + 16, the easiest way is to find out 2 different values that will add up to b but when multiplied is positive 16. Given that the only solution to this equation above is x = 4. the factored out form should be (x - 4)^2 or (x-4)(x-4). As b should be the addition of these two x values, b should be -8. The correct option is the second option, b = -8.

Answer from: plzzhelp7931

Answer from: gomek

I believe the answer is b=-8

Step-by-step explanation:

To factor out x2 + bx + 16, the easiest way is to find out 2 different values that will add up to b but when multiplied is positive 16.

Given that the only solution to this equation above is x = 4. the factored out form should be (x - 4)^2 or (x-4)(x-4).

As b should be the addition of these two x values, b should be -8.

Answer from: svarner2001

I believe the answer is b=-8

Step-by-step explanation:

To factor out x2 + bx + 16, the easiest way is to find out 2 different values that will add up to b but when multiplied is positive 16.

Given that the only solution to this equation above is x = 4. the factored out form should be (x - 4)^2 or (x-4)(x-4).

As b should be the addition of these two x values, b should be -8.

Answer from: Quest

angle uzt is congruent to angle tzy. angle vzw is congruent to angle yzx.

(credits to leowren)

step-by-step explanation:

Answer from: Quest

the system of inequity is

$y\leq -x+4$

$3y> x$

step-by-step explanation:

from the given graph it is noticed that we have two related lines. one is solid and another is dashed.

if a line passing through two points, then the equation of line is

$y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)$

the solid line passing through the points (0,4) and (4,0).

$y-4=\frac{0-4}{4-0}(x-0)$

$y=-x+4$

the related equation of solid line is $y=-x+4$ .

similarly, find the related equation of dashed line. the dashed liune passing through the points (0,0) and (3,1).

$y-0=\frac{0-1}{3-0}(x-0)$

$3y=x$

the related equation of dashed line is $3y=x$

from the given graph it is noticed that the point (0,1) lies on the shaded region, therefore the point (0,1) must be satisfied by the related equations.

check the related equations by the point (0,1).

$1=-0+4$

$1=4$

this statement is true if the sign of inequality is < instead of equality. since it is an solid line therefore the sign of inequality will be $\leq$ . the required inequality is

$y\leq -x+4$

similarly, check the second related equation.

$3(1)=0$

it is a dashed line, so this statement is true if the sign of inequality is > . the required inequality is

$3y> x$

15 points write a system of inequalities to represent the shaded portion of the graph

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The only solution of the equation x2 + bx + 16 = 0 is x = 4. what is the value of b?

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