Aquadratic equation of the form 0 = ax2 + bx + c has one real number solution. which could be the equation?

0 = 2x2 – 4x + 1
0 = 2x2 – 5x + 3
0 = –2x2 – 4x – 2
0 = –2x2 – 3x – 1

0 = –2x² – 4x – 2  would be the equation .

Step-by-step explanation:

Given : A quadratic equation of the form 0 = ax² + bx + c has one real number.

To find :  Which could be the equation

Solution.  0 = –2x² – 4x – 2   .

Tanking -2 common from equation we get,

 0 = –2(x² +2x + 1) .

On dividing by -2 both side ,

 0 = (x² +2x + 1)

This is the standard form of quadratic equation .

Therefore , 0 = –2x² – 4x – 2  would be the equation .

asdsad

step-by-step explanation:

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).