Isabella saved $15,000 and bought a car that cost $12,700. the insurance for the car
will cost $600 per year. how many full years will isabella be able to pay for car
insurance with her remaining savings?

3 years

Step-by-step explanation:

The following are given in the question:

ISS = Isabella's saving = $15,000

COC = Cost of the car = $12,700

COI = Cost of insurance = $600 per year

Step 1: Calculation of saving remaining after car purchase

SRACP = ISS - COC (1)

Where SRACP denotes saving remaining after car purchase.

Substituting the values above into equation (1), we have:

SRACP = $15,000 - $12,70 = $2,300

Therefore, the saving remaining after car purchase is $2,300.

Step 1: Calculation of the number of full years the remaining saving can cover car insurance

NFYRSCI = SRACP ÷ COI (2)

Where NFYRSCI denotes the number of full years the remaining saving can cover car insurance.

Also, substituting the values above into equation (2), we have:

NFYRSCI = $2,300 ÷ 600 = 3.83 years or 3 full years

Therefore, the number of full years the remaining saving can cover car insurance is just 3 full years.

Note that we are concerned about full years. Therefore, the decimal numbers of 0,83 (i.e. 3.83 - 3 = 0.83) which gives 10 months (i.e. 0.83*12 = 10 months) is not relevant since it is not up to a year.

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺