The segment joining the midpoints of sides pq and pr (the midsegment) in traingle pqr has length 8x^12x+36. if the length of qr is 4x^2+60x+120, find all possible measures of the midsegment

The possible measures of the midsegment are 32 units and 212 units.

Step-by-step explanation:

Given:

A triangle PQR with the midsegment made by sides PQ and PR has length equal to and the base length QR opposite to the midsegment is .

From midsegment theorem, we know that, the midsegment is a line parallel to the base opposite to it and half the length of the base length.

Therefore, Midsegment = Base length QR

Now, midsegment can be calculated using the values of 'x'.

First, plug in -1 for 'x'. This gives,

Now, plug in 4 for 'x'. This gives,

Therefore, the possible measures of the midsegment are 32 units and 212 units

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

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