There are10 boxes in a grab bag. seven of themcontains $20
bills. a contest winner gets to pick two boxesfrom the grab bag.
what are the probability of getting
two $20 bills?

7/15

Step-by-step explanation:

7 boxes out of 10 contain $20. Therefore 3 boxes do not have $20 bills.

The probability of picking a bag with a $20 bill

= 7/10

The probability of picking another bag with $20 bill

= (7-1)/(10-1)

= 6/9

The probability of getting  two $20 bills.

= 7/10 × 6/9

= 42/90

= 7/15

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length