The population of deer in a certain national park can be approximated by the function p(x)=150(1.07)^x, where x is the number of years since 1995. in which year will the population reach 300? hint: an answer such as 2002.4 would represent the year 2002.
a.2026
b.2005
c.2038
d.2016

B. 2005

Step-by-step explanation:

We have been given that population of deer in a certain national park can be approximated by the function , where x is the number of years since 1995. We are asked to find the year in which population will reach 300.

To solve our given problem, we will equate and solve for x as:

Now, we will take natural log on both sides as:

Now, we will find 10 years after 1995 that is .

Therefore, the population will be 300 in year 2005 and option B is the correct choice.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

no this is a nonlinear negative