The units digit of a two-digit number is twice the tens digit. if the digits are reversed, the new number is 9 less than the original number. what is the original number?

36

Step-by-step explanation:

Here is the correct and complete question: The units digit of a two-digit number is twice the tens digit. If the digits are reversed, the new number is 9 less than twice the original number. What is the original number?

Lets assume the original number be"10y+x". (x is unit digit and y is 10th digit)

∴ if number is reversed then resulting number be "10x+y".

As given: x= 2y

        and

Now, solving the equation to get original number.

Distributing 2 to 10y and x, then opening the parenthesis.

⇒

subtracting by (2x+y) on both side.

⇒

subtituting the value of "x", which is equal to 2y.

∴

⇒

subtracting both side by (16y-9)

⇒

cross multiplying

We get,

y=3

∵x= 2y

∴ x= 6

Therefore, the original number will be 36 as x is the unit number and y as tenth number.

the answer is c. hope this !

step-by-step explanation:

idk

step-by-step explanation:

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