You get one lottery ticket that will 5% of the time pay out $5, will 10% of the time pay out $10, and will 85% of the time pay out $1. 2. you get two lottery tickets, a and b. ticket a will pay $5 half of the time and $0 otherwise. ticket b will pay double your winnings from ticket a half of the time; otherwise ticket b pays $1. calculate the expected value (expected payout) of both scenarios. which would you prefer? explain why.

expected payout for case 1: $2.1

expected payout for case 2: $5.5

I prefer the second scenario.

Step-by-step explanation:

First scenario:

- you get paid $5 with probability 0.05

- $10 with probability 0.1

- $1 with probability 0.85

So the expected value is

E = 5*0.05+10*0.1+1*0.85 = 2.1

Second Scenario:

- you get paid $5 from A and $10 for B (a total of $15) with probability 0.25 (this is, if B doubled the value of A)

- you get paid $5 from A and $1 from B (a total of $6) with probability 0.25

-you get paid $0 from A and $0 from B with probability 0.25

- you get paid $0 from A and $1 from B with probability 0.25

Hence the expected value in this case is

E = 15*0.25+6*0.25+0*0.25+1*0.25 = 5.5

Even though in the second scenario you are more likely to gain less money (for one try), the expected value is much higher, so i prefer the second scenario.

answer: x= -2y

step-by-step explanation:

x = 17

step-by-step explanation:

1st step: isolate x.

24 - 3x = -27

-24         -24

-3x   =   -51

2nd step: divide.

-3x     =   -51

  3             3

  x       =     17

hope this