At what temperature will 5.00 g of Cl, exert a pressure of 900. torr at a volume of 750. mL

mark me as brainliest

154°C

Given,

n

=

5.00

g

⋅

mol

71

g

≈

7.04

⋅

10

−

2

mol

V

=

0.750

L

P

=

900

mmHg

⋅

atm

760

mmHg

≈

1.18

atm

Recall,

P

V

=

n

R

T

Hence,

⇒

T

=

P

V

n

R

≈

154

°

C

is the temperature at which this gas will behave in accordance with those parameters, given ideal behavior.

hi my dude or dudette

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3