Which ordered pair is a solution of system 2x-y< 5 and x +2y > 2

a) (1,-1)
b) (4,1)
c) (2,0)
d) (3,2)

D

Step-by-step explanation: When you plug 3 into where x in the first equation and plug 2 in for y. When you do that you get 6-2<5, 6-2 is 4 and 4 is less than 5, so this makes this equation true. For the second equation you do the same. 3 goes into the x spot and 2 into the y, after doing this you get 3+2(2)>2, 3 times 4 is 12 and that is greater than 2, hich also means that equation is ture. So there you have both equations are ture and that is how you get your answer.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer:   c ?

step-by-step explanation: