One warehouse had 185 tons of coal, another one has 237 tons. the first warehouse delivered 15 tons of coal to its clients daily, the second one delivered 18 tons of coal to its clients daily. in how many days will the second warehouse have 1.5 times more coal than the first one?

9 days

Step-by-step explanation:

Converting the question above to simultaneous equations

For warehouse 1

X = 185 - 15d eqn1

For warehouse 2

Y = 237 - 18d eqn2

From the question given, we need to find the value of d at which Y = 1.5X

237 - 18d = 1.5(185-15d)

237 - 18d = 277.5 - 22.5d

22.5d - 18d = 277.5 - 237

4.5d = 40.5

d = 40.5/4.5

d = 9

Therefore, it takes 9 days for the second warehouse have 1.5 times more coal than the first one