Write an equation in slope intercept form for the line that passes through (-4,2) and is parallel to 6x-3y=15

y = 2x + 10

Step-by-step explanation:

Two lines are said to be parallel if they have the same slope.

The given line is 6x - 3y = 15 , to find the slope of the line , we will make y the subject of the formula , that is

6x - 3y = 15

6x - 15 = 3y

dividing through by 3 , we have

2x - 5 = y

Therefore : y = 2x - 5

comparing with the formula of line in slope - intercept form

y = mx + c

where m is the slope

therefore , the slope is 2

since the new equation of the line is parallel to the one above , that means the slope is also 2.

To find the equation of the line , we will use the formula for calculating equation of line in slope - point form

y - = m ( x -

= -4

= 2

m = 2

Substituting into the formula , we have

y - 2 = 2 ( x - {-4} )

y - 2 = 2 ( x + 4 )

y - 2 = 2x + 8

adding 2 to both sides , we have

y = 2x + 10

it should be a and d. lmk if i'm wrong xd