Atank contains 60 kg of salt and 1000 l of water. pure water enters a tank at the rate 6 l/min. the solution is mixed and drains from the tank at the rate 3 l/min. (a) what is the amount of salt in the tank initially?
amount = (kg)

(b) find the amount of salt in the tank after 4.5 hours.
amount = (kg)

(c) find the concentration of salt in the solution in the tank as time approaches infinity. (assume your tank is large enough to hold all the solution.)
concentration = (kg/l)

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

(i) Set up an expression for the rate of change of salt concentration.

(ii) Integrate the expression

(iii) Find the constant of integration

(iv) Solve for A as a function of time.

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

b.Calculate the concentration

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is  

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

(c) Concentration at infinite time

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .