Atank contains 60 kg of salt and 1000 l of water. pure water enters a tank at the rate 6 l/min. the solution is mixed and drains from the tank at the rate 3 l/min. (a) what is the amount of salt in the tank initially?
amount = (kg)

(b) find the amount of salt in the tank after 4.5 hours.
amount = (kg)

(c) find the concentration of salt in the solution in the tank as time approaches infinity. (assume your tank is large enough to hold all the solution.)
concentration = (kg/l)

(a) 60 kg; (b) 21.6 kg; (c) 0 kg/L

Step-by-step explanation:

(a) Initial amount of salt in tank

The tank initially contains 60 kg of salt.

(b) Amount of salt after 4.5 h

(i) Set up an expression for the rate of change of salt concentration.

(ii) Integrate the expression

(iii) Find the constant of integration

(iv) Solve for A as a function of time.

(v) Calculate the amount of salt after 4.5 h

a. Convert hours to minutes

b.Calculate the concentration

c. Calculate the volume

The tank has been filling at 6 L/min and draining at 3 L/min, so it is filling at a net rate of 3 L/min.

The volume added in 4.5 h is  

Total volume in tank = 1000 L + 810 L = 1810 L

d. Calculate the mass of salt in the tank

(c) Concentration at infinite time

This makes sense, because the salt is continuously being flushed out by the fresh water coming in.

The graph below shows how the concentration of salt varies with time.

plants store their excess carbohydrate in the form of starch so that it could be used as energy source later on. the excess carbohydrate is converted into starch in the plastid i.e. chloroplast & this process occurs in the presence of sunlight. it is an insoluble polymer of glucose which gets stored in cell organelles named as amyloplasts. in some plants, starch is also stored in roots and embryos.

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a