The local appliance store is offering 15% off an entire purchase of $2,000 or more; or 30% off a single
item of $1,000 or more. use the prices listed above to determine which offer will save the most
money on these appliances?

The offer of 30% off a single item of $ 1000 or more will save most money on these appliances .

Step-by-step explanation:

Given as :

The purchase price = $ 2000

The offering discount = 15 %

Let The price of item after discount = x

So , x = ( $ 2000 ) - ( $ 2000 × 15 % )

Or,  x = ( $ 2000 ) - ( $ 2000 × 0.15 )

Or,  x = ( $ 2000 ) - ( $ 300 )

∴     x =  $ 1700

Now, Again

The purchase price = $ 1000

The offering discount = 30 %

Let The price of item after discount = y

So , y = ( $ 1000 ) - ( $ 1000 × 30 % )

Or,  y = ( $ 1000 ) - ( $ 1000 × 0.3 )

Or,  y = ( $ 1000 ) - ( $ 300 )

∴     y =  $ 700

Now, If we purchase two item at the cost price of $ 700 each , then it will cost as $ 700 × 2 = $ 1400

And for the same number of items at the cost price is $ 1700 after 15 % discount on list price of $ 2000 , So the second offer will save most .

Hence The offer of 30% off a single item of $ 1000 or more will save most money on these appliances . Answer

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204