Maria and kim left town at 9: 00 am and traveled the same route in separate cars. kim drove 3 h at a steady speed, then slowed down 15km/h for 3 more hours. maria averaged 5 km/h more than kim's original speed for the entire trip and arrived at their destination at 2 pm. what was kim's original speed?

70 km/h

Step-by-step explanation:

Let the original speed of Kim = x km/h

Kim drove with this speed for 3 hours.

Total distance covered by Kim during this period is 3 * x km

After 3 hours , Kim slowed down by 15 km/h.

So, new speed of Kim is (x-15) km/h

Kim drove at this speed for another 3 hours .

Distance covered by Kim during this period = 3 * (x-15) km

So, total distance covered by Kim is \[3x + (3x-45)\] km

This is equivalent to \[6x - 45\] km

Maria's speed = (x+5) km/h

Maria started at 9 am and reached the destination at 2 pm. So she drove for 5 hours.

Total distance covered by Maria is \[5 * (x+5)\] km

This is equivalent to \[5x + 25\] km

As per the given data, 6x - 45 = 5x + 25

=> 6x - 5x = 45 + 25

=> x = 70

So Kim's original speed was 70 km/h

5 x 14?

im new, sorry if this is wrong.

step-by-step explanation:

i dont understand the question? ?

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