Jester 2
which values of c will cause the quadratic equation -2 + 3x + c = 0 to have no real number solutions? check all that
apply.

For all c less than ,the given quadratic equation has no real number solutions.

Step-by-step explanation:

Given

Quadratic Equation

On comparing with general form of Quadratic Equation

we have,

For no real number solution we must have

So, For all c less than ,the given quadratic equation has no real number solutions.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

2

step-by-step explanation: