74. What is the empirical formula for a compound which contains 73.9%Hg and 26.1% Cl

Hg is the empirical formula for a compound which contains 73.9%Hg and 26.1% Cl.

Explanation:

given that:

Hg = 73.9 %  atomic mass of Hg= 200.59

Cl = 26.1        atomic mass of Cl= 35

let us assume that this percentage is in 100 grams.

number of moles =

number of moles of Hg =

                                        = 0.363 moles

number of moles of Cl =

                                      = 0.735 moles

molar ratio of  Cl and Hg  =

                                        =  2:1

In emperical formula first cation then anion is written.

We can see that Cl is twice the number of Hg. So the formula is

Hg is the empirical formula

b is the correct answer

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