Arock is thrown upward with an initial velocity of 122 feet per second. the height of the rock ,(h), in feet after t seconds is given by the function ℎ() = −162 + 122 + 10.how long does it take the rock to reach its maximum height? what is the rock’s maximum height. round to the nearest hundredth, if necessary.

the maximum height is 231.118 feet

Step-by-step explanation:

Initial velocity, u = 122 feet per second.

The height of the rock ,(h), in feet after t seconds is given by the function ℎ(t) = −162x^2 + 122x + 10.

Acceleration of the object is 32.17405 ft/s2. This is approximately 32.2 ft/s2. It is same as the acceleration due to gravity. Since the object is moving upwards, the acceleration will be negative because it is moving in the opposite direction of the gravitational force.

Therefore

g = - 32.2 ft/s^2

The final velocity, v = 0 at maximum height.

Applying Newton's equation of motion,

v^2 = u^2 + 2gh

0 = 122^2 + (-32.2 × 2 ×h)

0 = 14884 - 64.4h

64.4h = 14884

h = 14884/64.4 = 231.118 feets( approximated to the nearest hundredth)

step-by-step explanation:

how many centimeters did the level of the salsa go down by?

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.