You have two pieces of wood that will make up two sides of a triangular picture frame. one is 6 in. long and the other is 7 in. long. what is the range of the possible lengths for the third side of the frame?

13 > L > 1

Step-by-step explanation:

We have two pieces of wood, one is 6 inches long and the other is 7 inches long. They make two sides of a triangle.

Now, we have to get what will be the third side.

The length of the third side will be maximum when the angle between the sides of 6 in and 7 in will be close to 180°.

Therefore, the maximum length of the third side should be < (6 + 7) i.e. 13 inches.

Again, the length of the third side will be minimum when the angle is close to 0°.

That means the minimum length of the third side will be > (7 - 6) i.e. 1 inch.

Therefore, the range of length (L) of the third side is 13 > L > 1. (Answer)

the answer is a

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3