An elevator has a placard stating that the maximum capacity is 1610 passengers. so, 10 adult male passengers can have a mean weight of up to1610 divided by 10 = 161 pounds. if the elevator is loaded with 10 adult male passengers, find the probability that it is overloaded because they have a mean weight greater than161lb. (assume that weights of males are normally distributed with a mean of 165 lb and a standard deviation of 35 lb.)does this elevator appear to be safe? the probability the elevator is overloaded is? (round to four decimal places as needed.)

We are supposed to find  the probability that it is overloaded because they have a mean weight greater than 161 lb.

n = 10 males

P(X>161)

Formula :

Refer the z table

P(z<−0.3614)=0.6406

P(x>161)=1-P(x<161)=1-P(z<−0.3614)=1-0.6406=0.3594

The probability the elevator is overloaded is 0.3594

The elevator is safe since the probability of overload is less than 0.5

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

b, i believe, but not sure.