Atotal of $76,000 is to be invested, some in bonds and some in certificates of deposit (cds). if the amount invested in bonds is to exceed that in cds by $6,000, how much will be invested in each type of investment

The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000

Step-by-step explanation:

Given as :

The total amount to be invested as bonds and certificates of deposit (CD) = $76,000

Let the amount invested as bonds = $ x + $6000

And The amount invested as CD = $ x

Now, According to question

The amount invested as CD + The amount invested as bonds = $ x  + $ x + $6000

Or, $ x  + $ x + $6000 = $76,000

Or, $ 2x = $76,000 - $6000

So,  $ 2x = $70,000

∴  x = = $ 35,000

And $ x + $6000 = $ 35,000 + $6000 = $ 41,000

Hence The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000    Answer

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value

i got 10.28 but that rounds up to 10.3