Which system of equations is graphed on this coordinate plane

y=(3x/2)+3 and y=(-1x/2)-1

Step-by-step explanation:

So what I did was use rise/run to find the slope of the equation. Let's focus on the line going from the bottom left to the top right corner. For this line, I would start on (-2,0) which is one of the points plotted on your number line and count how much it is away from (0,3). You should get 3 units. After this, count how much it is to the right which is 2 units. Now, use rise/run to find the slope. 3/2, therefore the slope of the line is 3x/2.  Now all we need is the y-int. For the Y int, all we have to do is see where the line touches the Y-axis which in this case is at (0,3). So your y-int would be 3. Now we can use this information to craft an equation in the form y=mx+b, m being the slope and b  being the y int. We should get y=(3x/2)+3. Now repeat this with the other line to find the equation, but be careful!!! It has a negative slope.

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral

part a

x     y

0     8

1     7.5

2     7

3     6.5

4     6

5     5.5  

for every hour i deducted .5 inches from the length of the candle

part b

it is a function because for every x value there is only one y value

part   c

for every x value there is only one y value

x       y

0       8

1       7.6

2       7.2

3       6.8

step-by-step explanation: