An object is launched directly in the air at a speed of 64 feet per second from a platform located 16 feet in the air. the motion of the object can be modeled using the function f(t)=−16t2+64t+16, where t is the time in seconds and f(t) is the height of the object. when, in seconds, will the object reach its maximum height? do not include units in your answer.

After 2 seconds the object reach its maximum height of 80 feet.

Step-by-step explanation:

Consider the provided function.

The function is a downward parabola.

The object will reach its max height at the vertex of the parabola.

The vertex of the parabola is given by ,

Where the standard form is .

By comparing the provided function with the standard form.

a=-16, b=64 and c=16

Thus, the vertex are:

Now substitute the value of t in the provided function.

Hence, after 2 seconds the object reach its maximum height of 80 feet.

answer: $34.31

step-by-step explanation:

$11.99 x 3 = $35.97

$35.97 - 10% = $32.37

$32.37 + 6% = $34.31

answer: 1722

step-by-step explanation:

given: the mass of saturn=

the mass of mercury=

the number of times the mass of saturn is greater than the mass of mercury

hence, the mass of saturn is 1722 times greater than the mass of mercury.