In quadrilateral PQRS, Angle P Q R measures (7x - 2)o . Angle PSR measures (5x + 14 )o.

Circle T is inscribed with quadrilateral P Q R S.

What are the measure of angles PQR and PSR?

m Angle P Q R = 54o and m Angle P S R = 54o

m Angle P Q R = 84o and m Angle P S R = 96o

m Angle P Q R = 90o and m Angle P S R = 90o

m Angle P Q R = 96o and m Angle P S R = 84o

Fourth option is correct m Angle P Q R = 96 and m Angle P S R = 84

Therefore,

Step-by-step explanation:

Given:

In quadrilateral PQRS,

∠PQR = (7x - 2)°

∠PSR = (5x + 14)°

Circle T is inscribed with quadrilateral P Q R S.

To Find:

m∠PQR = ?

m∠PSR  = ?

Solution:

Circle T is inscribed with quadrilateral P Q R S.

Therefore,

Quadrilateral PQRS is a Cyclic Quadrilateral,

So for a Cyclic Quadrilateral, opposite Angles are Supplementary

∠PQR and ∠PSR are opposite angles

∴

Substituting the values we get

Substitute x in PQR and PSR we get

Therefore,

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2

29 is the correct answer

step-by-step explanation: