Achild bounces a 48 g superball on the sidewalk. the velocity change of the super bowl is from 23 m/s downward to 14 m/s upward. if the contact time with the sidewalk is 1800 s, what is the magnitude of the average force exerted on the superball by the sidewalk?

= 0.0009866 N

Step-by-step explanation:

For resolving this problem we can use the impulse-momentum theorem; this theorem establishes that  the change in momentum of an object equals the impulse applied to it

The impulse is defined how:

I = Δt

    :   Average force

    Δt =  Time interval

Then:

Δt

(0.048)(14) - (0.048)(-23) = (1800)

0.672 + 1.104 = 1800

1.776 = 1800

=

= 0.0009866 N

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.