The lengths of the sides of a triangle are 3, 3, 3 square root 2 can the triangle be a right triangle?

Step-by-step explanation:

If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2

9 + 9 = C^2

18 = C^2

C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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