4. X varies directly with the square of y, where x>0, and y >0. If x= 3 when y = 5, then what is the value
ofy when x= 48?

The value of y, when x = 48 is y = 12/5

Step-by-step explanation:

The given parameters are;

x is directly proportional to y

Where x > 0, y > 0

For x = 3. y = 5

Therefore, we have;

x ∝ a·y²

For ,x = 3, when y = 5, we have;

3 = a × 5² = 25·a

∴ a = 25/3

When x = 48, we have;

48 = 25/3×y²

y² = 3/25 × 48 = 144/25

y = √(144/25) = 12/5

y = 12/5

The value of y, when x = 48 is y = 12/5.

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb