If a projectile is launched vertically upward from the ground with an initial velocity of 70 ft per sec, neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by s equals negative 16 t squared plus 70 t. which equation should be used to determine the time at which the height of the projectile reaches 10 ft?

Step-by-step explanation:

Given that a projectile is launched vertically upward from the ground with an initial velocity of 70 ft per sec

Neglecting air resistance, its height s (in feet) above the ground t seconds after projection is given by

When height = 10 feet we have to find the time

Hence substitute s = 10 ft

We may get two answers as

The first time is for going up and the second is for coming down.

00

step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!