C. cross multiply the ratios in part b to get a simplified equation
d. complete the proportions to compare the first and third triangle • c/a=
e. cross multiple the ratios in part d to get a simplified equation
f. complete the steps to add the equations from parts c and e. this will make one side of the pythagorean’s theorem. • part c: b^2=__
part e: a^2=__
a^2+b^2=__
g. factor out a common from part f. • a^2+b^2++
h. finally, replace the expression inside the parentheses with one variable and then simplify the equation to a familiar from. hint: look at the large triangle. • a^2+b^2=
a^2+b^2=__

a is 8.b is 10.c is 10.5. d is -.5

step-by-step explanation:

just minus the smallest number from the biggest.

the weight of the object inside the box!

6(h+1)/2=a

a=area

step-by-step explanation:

its the same thing as a square or rectangle but after multiplying two sides you need to divide it by two.

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.