At a certain temperature, the equilibrium constant, K c , is 0.00376 for the reaction Cl 2 ( g ) − ⇀ ↽ − 2 Cl ( g ) A. If 3.45 g Cl 2 is placed in a 3.50 L flask at this temperature, what are the equilibrium concentrations of Cl 2 and Cl ?

Equilibrium concentration of Cl₂ = 0.013 molar

Equilibrium concentration of Cl = 0.0072 molar

Explanation:

                            Cl ₂ ( g ) ⇄ 2 Cl ( g )

No. of moles of Cl₂(g) =

                                    =

                                    = 0.048 mole

Concentration of Cl₂ = M = 0.013 molar

                        From the above equation we get

                      =

                      [Cl]² = Kc X [Cl₂]

                               = 0.00376 x 0.013

                               = 5.22 x 10⁻⁵ molar

                     [Cl] = 0.0072 molar

am i too late?

explanation:

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )