One jogger begins his run on a path at a rate of 6 miles per hour. a second jogger starts at the same point of the path as the first jogger, but jogs at a rate of 6.5 miles per hour. the second jogger begins 15 minutes after the first jogger. how long will it take the second jogger to catch up to the first jogger?

The answer to your question is: three hours.

Step-by-step explanation:

data

Jogger 1 = 6 mi/h

Jogger 2 = 6.5 miles/h , starts 15 min (0.25 h) after the first Jogger

Time when the second jogger catch the first jogger = ?

Process

Advantage of the first jogger    d = vt = 6(0.25) = 1.5 mi

Distance where they meet       1.5 + 6t = 6.5t

Find the t value                          6.5t - 6t = 1.5

                                                   0.5 t = 1.5

                                                    t = 1.5 / 0.5

                                                    t = 3 hours                                                    

can someone answer this question plz

step-by-step explanation: