If f(x)= 3-2 and g(x)=1/x+5 what is the vue of (f/g) (8)

The value of (f/g) (8) = -169

Step-by-step explanation:

Step 1: explaining the question

The quotient (f/g) is not defined at values of x ⇒  both the functions must be defined at a point for the combination to be defined.

⇒(f/g)(x) =(f(x)) / (g(x))

If f(x)= 3-2 and g(x)=1/x+5

⇒then according to the preceding formula: (f/g)(x) =(f(x)) / (g(x))

⇒(f/g)(8) = f(8) / g(8)

to solve this we have to find the value of both f(8) and g(8)

Step 2: find value of f(8) and g(8)

⇒ we know that f(x) = 3-2x and we know dat f(x) = f(8)

⇒ f(8) = 3-2(8)

f(8) = 3-16 = -13

⇒we know that g(x) = 1/x+5  and g(x) = g(8)

⇒ g(8) = 1/8+5

g(8) =1/13

These 2 equations we will insert in the following : ⇒(f/g)(8) = f(8) / g(8)

⇒ f/g (8) = -13 / (1/13) = -13 * 13/1 = -169

The value of (f/g) (8) = -169

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!