, so that 
(which appears in the first term on the left side):
, and we don't have to find any integrating factor because the left side is already the derivative of a product:
, we get
Solve the following initial value problem: 2xyy'+y^2-4x^3=0. where y(1)=2
the answer is y= sq...
Mathematics, 13.09.2019 18:30 aliami0306oyaj0n
Solve the following initial value problem: 2xyy'+y^2-4x^3=0. where y(1)=2
the answer is y= sqrt((x^4+3)/x)
Answers: 1
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