The probability for event a is 0.3, the probability for event b is 0.6, and the probability of events a or b is 0.8. why are the events not mutually exclusive? the sum of p(a) and p(b) is less than p(a or b). the product of p(a) and p(b) is less than p(a or b). the product of p(a) and p(b) is not equal to p(a or b). the sum of p(a) and p(b) is not equal to p(a or b).

The sum of P(A) and P(B) is not equal to P(A or B).

Step-by-step explanation:

We have that:

The probability for event A is 0.3, P(A)=0.3

The probability for event B is 0.6  P(B)=0.6 and  

The probability of events A or B is 0.8, P(A or B)=0.9

For mutually exclusive events,

Let us check and see if this is true

......This is not true

Therefore events A and B are not mutually exclusive because the sum of P(A) and P(B) is not equal to P(A or B).

answer:

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

explanation:

service only with 20% tip  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

in the opening of the question the word 'service' is associated only with the pretax value.

the closing part of the question asks: how much did she pay for the  

service

−−−−−−  

so technically the answer is  

→

$

72.6

(

1

+

20

100

)

=

$

87.12

however, the intention of the question provider may have been that your answer is to be  

$

87.12

(

1

+

8

100

)

=

$

94.09

to 2 decimal places.

'

payment just for service  

→

$

87.12

payment for service including tax

→

$

94.09

tony b

mar 21, 2017

answer:

trying to explain it another way

explanation:

service charge  

.

→

$

72.60

20% tip  

20

100

×

$

72.60

=

$

14.52

−−−−−−  

←

add

$

87.12

tax  

8

100

×

$

87.12

=

$

6.97

−−−−−  

←

add

$

94.09

related questions

all it means is function 3