The parametric equations for the paths of two projectiles are given. at what rate is the distance between the two objects changing at the given value of t? (round your answer to two decimal places.) x1 = 8 cos(2t), y1 = 6 sin(2t) first object x2 = 6 cos(t), y2 = 4 sin(t) second object t = π/2

the answer is d. 75%

1 3 5

step-by-step explanation:

i took the test: )

if you need just tell me and i will come to the rescue.

step-by-step explanation:

(b) 240

step-by-step explanation:

first, we use the pythagorean formula using the given side lengths to find x. then we use x to find the side lengths. then we add the side lengths to find the perimeter.

pythagorean theorem formula:

a^2 + b^2 = c^2

(x - 20)^2 + (x - 40)^2 = x^2

x^2 - 40x + 400 + x^2 - 80x + 1600 = x^2

x^2 -120x + 2000 = 0

(x - 100)(x - 20) = 0

x - 100 = 0 or x - 20 = 0

x = 100 or x = 20

we see that the solution x = 20 must be discarded because it will give a negative side length and a side length of 0. the only valid solution is x = 100.

perimeter = sum of the lengths of the sides

perimeter = x + x - 20 + x - 40

perimeter = 3x - 60

replace x with 100.

perimeter = 3(100) - 60

perimeter = 300 - 60

perimeter = 240