Tom says that he needs 6 rolls to obtain each possible outcome on a 6-sided die. on the fourth roll, he rolls his second "3". tom says that the die is loaded and that each outcome is not equally likely. is tom correct here? if you think tom is incorrect, how many rolls should tom make until he sees each number occurring about 1/6 of the time?

Tom is incorrect

Step-by-step explanation:

The odds of getting any number on a 6-sided die are

Every time he rolls, there is a chance he gets any number.  Therefore, it is totally plausible to get the same number again.  As the number of rolls tends toward infinity, the ratio of each number occurring to number of rolls equals .  

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.